Hi,

I forgot to mention that my OS is running simultaneously with L4Linux.

In this case, it seems that Thread::transfer_fpu() becomes a no-op -- since the vcpu task for L4Linux has the FPU, but is the owner of FPU, and my OS doesn't. Therefore my OS cannot grant my user-level task the FPU since it doesn't have it.

However, my OS can grant the FPU to my user-level task, once I insert an floating-point instruction right before trying to grant my user-level process the FPU. In this case my OS magically becomes the owner of the FPU, and everything works smoothly.

What I really don't understand is that how this "magic" works. First, both L4Linux and my OS are started independently by ned:

(1) If FPU ownership can only be transferred via exception #7 and IPC, I don't understand why my OS can grab the FPU transparently, simply by executing an floating-point instruction.

(2) If there's some transparent way that an process can get an FPU, then I don't understand why my user-level process can't grab the FPU transparently. Maybe this is because that my OS is a non-alien task but my user-level task is an alien?

I really appreciate if you can explain it a little bit --- I'm really appreciated if you can share your idea of what would be the correct way of implementing it.

~Haohui

On Tue, Apr 10, 2012 at 5:07 PM, Adam Lackorzynski <adam@os.inf.tu-dresden.de> wrote:

On Sun Apr 08, 2012 at 17:22:21 -0500, Mai, Haohui wrote:
> I'm writing a new OS kernel atop of L4Fiasco.OC. I'm having some
> difficulties to let my OS support user-level processes that uses
> floating-point instruction.
>
> So far, My OS closely follows L4Linux, it creates a new task for each
> user-level process, and marks as all threads of the task as alien thread to
> capture all page faults and exceptions.
>
> My OS works fines with page fault and syscalls. However, I'm confused with
> what I should do with floating-point exception (exception #7), which is
> issued to my kernel at the first time it tries to perform floating-point
> arithmetic.
>
> I tried to return to the user-level process with an empty message (
> l4_msgtag_t tag = l4_msgtag(0, 0, 0, 0) ), or an empty message with
> L4_MSGTAG_TRANSFER_FPU (l4_msgtag_t tag = l4_msgtag(0, 0, 0,
> L4_MSGTAG_TRANSFER_FPU) ), but I had no luck.
>
> The user-level process immediately calls "int $0x3" and stops.
>
> I read through L4Linux's code and it seems it's doing similar thing, except
> that it did initialize the FPU state before asking L4 to transfer the FPU
> state to user-level process.

I do not see anything (obvious) wrong. Can you pinpoint where the int3
is?




Adam
--
Adam                 adam@os.inf.tu-dresden.de
 Lackorzynski         http://os.inf.tu-dresden.de/~adam/

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