Its me again :-)

[Kermit the Frog]

Hello, 
	lets see if I have this thing right.

Lets say that main() creates a thread that will act as a scheduler. We'll
call it sched. Now main() creates antoher thread that will have sched as
its scheduler. sche() enters an infinite loop with a l4_i386_ipc_wait in
it. Of course, it waits for an preemption RPC message. 

Now, when creating the second thread (lets call it task) with
l4_thread_ex_regs, I put sched to be its preempter, anyway, sched() never
gets the IPC and task() runs as if it never had any preempter asociated.

Theres another thing, if inside main we put l4_thread_ex_regs to change
task()'s eip and esp to (dword_t) -1 (this would likely stop
task()) nothing happens, task() just runs normally.

Any ideas ??

Cheers.

PS: I didnt send any source code because its kind of long and I dont want 
to bother people w/unsolicited mail ;-), if anyone wants it please email me 
and ill be happy to send it

Cervi~no Ulises <kermit at tower.com.ar> <ulises at rosario.linux.org.ar>
...............................................................................
"Contrary to popular opinion, Unix is user friendly, It just happens to be 
 very selective about who it makes friends with."